5c^2+9c-80=0

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Solution for 5c^2+9c-80=0 equation:


Simplifying
5c2 + 9c + -80 = 0

Reorder the terms:
-80 + 9c + 5c2 = 0

Solving
-80 + 9c + 5c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-5 + -1c)(16 + -5c) = 0

Subproblem 1

Set the factor '(-5 + -1c)' equal to zero and attempt to solve: Simplifying -5 + -1c = 0 Solving -5 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -1c = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -1c = 0 + 5 -1c = 0 + 5 Combine like terms: 0 + 5 = 5 -1c = 5 Divide each side by '-1'. c = -5 Simplifying c = -5

Subproblem 2

Set the factor '(16 + -5c)' equal to zero and attempt to solve: Simplifying 16 + -5c = 0 Solving 16 + -5c = 0 Move all terms containing c to the left, all other terms to the right. Add '-16' to each side of the equation. 16 + -16 + -5c = 0 + -16 Combine like terms: 16 + -16 = 0 0 + -5c = 0 + -16 -5c = 0 + -16 Combine like terms: 0 + -16 = -16 -5c = -16 Divide each side by '-5'. c = 3.2 Simplifying c = 3.2

Solution

c = {-5, 3.2}

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